IGCSE & O-Level • Physics (0625)12 min read

Motion, Speed, Acceleration & Forces

Complete revision guide with worked equations, vector analysis, and exam tips

Must-Know Formulas for this Topic
Average Speed
v=stv = \frac{s}{t}
m/s\text{m/s}
Acceleration
a=v−uta = \frac{v - u}{t}
m/s2\text{m/s}^2
Newton's 2nd Law
F=maF = ma
N (Newtons)\text{N (Newtons)}
Weight
W=mgW = mg
N (with g=9.8 m/s2)\text{N (with } g = 9.8\text{ m/s}^2)
Kinematic Equation
v2=u2+2asv^2 = u^2 + 2as
Independent of time\text{Independent of time}

1. Scalar vs Vector Quantities in Motion

A scalar quantity has magnitude (size) only. Examples include distance, speed, time, mass, and energy.

A vector quantity has both magnitude and a specific direction. Examples include displacement, velocity, acceleration, force, and momentum.

In circular motion at constant speed, velocity is constantly changing because the direction of travel changes at every single point.

Examiner Pitfall Alert
  • Do not mix up distance and displacement: distance is total path length, displacement is straight-line distance from start to end with direction.

2. Distance-Time & Velocity-Time Graphs

On a Distance-Time (or Displacement-Time) graph, the gradient represents the speed (or velocity). A horizontal line indicates the object is stationary.

On a Velocity-Time graph, the gradient represents the acceleration.

Crucially, the area under a Velocity-Time graph represents the total distance travelled (displacement). For triangles use 1/2 × base × height; for trapezoids use 1/2(a + b) × h.

Area under v-t graph=Total Distance Travelled\text{Area under } v\text{-}t \text{ graph} = \text{Total Distance Travelled}
Examiner Pitfall Alert
  • Never calculate the area under a distance-time graph—it has no physical meaning!
  • If the curve on a v-t graph is non-linear, you must count squares or use the trapezoid rule to approximate the area.
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3. Falling Objects & Terminal Velocity

When an object is released from rest in a fluid (such as air), initial downward force is only weight (W = mg), so it accelerates at g (9.8 m/s²).

As speed increases, upward air resistance (drag) increases in proportion to velocity.

The net force downwards (F_net = W - Drag) decreases, causing downward acceleration to decrease.

Eventually, the upward drag force balances the downward weight (Drag = W). Resultant force is zero, so acceleration is zero. The object now moves at constant maximum speed called Terminal Velocity.

Fnet=W−Fdrag=0  ⟹  a=0F_{\text{net}} = W - F_{\text{drag}} = 0 \implies a = 0
Examiner Pitfall Alert
  • Examiner alert: 'Acceleration decreases' DOES NOT mean the object is slowing down! It is still speeding up, just at a slower rate until terminal velocity is reached.

Test Your Knowledge

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